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#47d01f34-e2b1-4607-844f-35b1a3c708c4简单解答题数列求通项方法数列

28.已知数列{an}\{a_{n}\}{bn}\{b_{n}\}的前nn项和分别为SnS_{n}TnT_{n},且b1=12{b_1}=\frac{1}{2}Sn=12n2+12n{S_n}=\frac{1}{2}{n^2}+\frac{1}{2}n,当n>1n>1时,满足2bnan1=bn1an2b_{n}a_{n-1}=b_{n-1}a_{n}. (1)求ana_{n}; (2)求TnT_{n}