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#780898a5-e5a3-45ef-bea8-eedc11195c7d中等解答题数列求通项方法数列

13.已知等差数列{an}\{a_{n}\}的前nn项和为SnS_{n}a5=9a_{5}=9S7=49S_{7}=49.数列{bn}\{b_{n}\}的前nn项和为TnT_{n}b1=1b_{1}=1Tn=bn+11T_{n}=b_{n+1}-1. (1)求数列{an}\{a_{n}\}{bn}\{b_{n}\}的通项公式; (2)设cn=an2bnc_n=\frac{a_n^2}{b_n},求数列{cn}\{c_{n}\}的最大项.